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The rate of a certain reaction is given ...

The rate of a certain reaction is given by, rate `=k[H^(+)]^(n)` The rate increase 100times when the pH change from 3 to 1. The order (n) of the reaction is—

A

2

B

0

C

1

D

`1.5`

Text Solution

Verified by Experts

The correct Answer is:
C
Reaction -rate `(r)=k[H^(+)]^(n)`
pH = 3 , So , `[H^(+)]=10^(-3)`
pH = 1 , So , `[H^(+)]=10^(-1)`
`therefore"Ratio of "r_(1) " to " r_(2) " is "-(r_(1))/(r_(2))=(k(10^(-3))^(n))/(k(10^(-1))^(n))`
or, `(1)/(100)=((10^(-3))/(10^(-1)))^(n)(becauser_(2)=100r_(1))`
or, `(10^(-2))^(1) = (10^(-2))^(n) `
or, n = 1
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