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For a first order reaction , Ararr Produ...

For a first order reaction , `Ararr` Products , the concentration of A changes from 0.1 (M) to 0.025(M) in 40 minutes . The rate of reaction when the concentration of A is 0.01 (M) , is -

A

`3.47xx10^(-4)(M)."min"^(-1)`

B

`3.47xx10^(-5)(M)."min"^(-1)`

C

`1.73xx10^(-4)(M)."min"^(-1)`

D

`1.73xx10^(-5)(M)."min"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
`k=(2.303)/(t)log.(a)/(a-x)`
`thereforek=(2.303)/(40)log.(0.1)/(0.025)=(2.303)/(40)log4=0.0347"min"^(-1)`
Given , `Ararr` Product
Thus, rate `k=[A]=0.0347xx0.01(M)."min"^(-1)`
`=3.47xx10^(-4)(M)."min"^(-1)`
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