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The rate constant of the reaction Ararr...

The rate constant of the reaction `ArarrB " is " 0.6xx10^(-3)"mol.L"^(-1).s^(-1)` . If the concentration of A is 5(M) , then concentration of B after 20 min is -

A

3.60 (M)

B

0.36 (M)

C

0.72 (M)

D

1.08(M)

Text Solution

Verified by Experts

The correct Answer is:
C
According to the unit of rate constant , the order of the reaction is zero.
`therefore[A]=[A]_(0)-kt`
`=(5-0.6xx10^(-3)xx20xx60)(M)=4.28(M)`
`therefore` After 20 min [A] = (5-4.28) (M) = 0.72 (M)
`therefore ` After 20min , [B] = 0.72 (M).
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