Show that , `t_(3//4)` of a first order reaction is twice the value of `t_(1//2)` of that reaction.

Explanation

`t_(3//4)=(1)/(k)In (a)/(a-3a//4)= (2xx2.303)/(k) log2,t_(1//2)=(2.303)/(k)log.(a)/(a-a//2)=(2.303)/(k)log2, therefore t_(3//4)=2xxt_(1//2)`