`2N_(2)O_(5)rarr4NO_(2)(g)+O_(2)(g)` , The above reaction is completed in a closed vessel . It is observed that the concentration of `NO_(2)` is increased by `4xx10^(-2)"mol.L"^(-1)` in 5 second . Calculate
the rate of reaction

Explanation

Reaction -rate =-`(1)/(2)(Delta[N_(2)O_(5)])/(Deltat)=(1)/(4)(Delta[NO_(2)])/(Deltat)=(Delta[O_(2)])/(Deltat)`
Reaction -rate `(1)/(4)(Delta[NO_(2)])/(Delta)`
`=(1)/(4)xx(4xx10^(-2))/(5)"mol.L"^(-1).s^(-1)`
`=2xx10^(-3)"mol.L"^(-1).s^(-1)`