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Cl(2)+2I^(-)rarr2Cl^(-)+I(2) , the conce...

`Cl_(2)+2I^(-)rarr2Cl^(-)+I_(2)` , the concentration of `I^(-)` falls from `0.35"mol.L"^(-1)" to " 0.25"mol.L"^(-1)` in 5min . What is the average rate of reaction ? Calculate the rate of formation of `I_(2)` .

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Average rate `=-(1)/(2)(Delta[I^(-)])/(Deltat)=-(1)/(2)xx((0.25-0.35)/(5))`
`=0.01"mol.L"^(-1)."min"^(-1)`
Rate of formation of `I_(2),(Delta[I_(2)])/(Deltat)` = average rate
`=0.01"mol.L"^(-1)."min"^(-1)`
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