In a first order reaction , the amount of reactant decomposed in the first 1 min is 1 % of its initial amount. What percent of the reactant will remain undecomposed after 1 hour from the start of the reaction ?

Explanation

`k = (2.303)/(t)log.(a)/(a-x)=(2.303)/(1) log.(a)/(a-0.01a)=0.01"min"^(-1)`
`t=(2.303)/(k) log .(a)/(a-x) " or, "60=(2.303)/(0.01) log. (a)/(a-x)`
or, a - x = 0.549 `xxa`
`therefore ` Percentage of undissociated substance
`=(0.549xxa)/(a)xx100=54.9%`