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The rate constant of decomposition of B ...

The rate constant of decomposition of B is `4.8xx10^(3)s^(-1) " at "15^(@)C` . If the activation energy of the reaction is 80 kJ.mol , at what temperature will the rate constant of the reaction be `1.5xx10^(4)s^(-1)` ?

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`log .(1.5xx10^(4))/(4.8xx10^(3))=(80xx10^(3))/(2.303xx8.314)((T_(2)-288)/(288xxT_(2)))`
`therefore T_(2) = 298.17k`
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