Home
Class 12
CHEMISTRY
1 mL of 10% NaCl solution is added to 10...

1 mL of 10% NaCl solution is added to 10 mL of gold sol in the presence of 0.0250 g starch when coagulation of that sol is just prevented . What is the gold number of starch ?

Text Solution

Verified by Experts

The quantity of starch =0.025 g =25 mg
`therefore ` Gold number of starch=25
Promotional Banner

Topper's Solved these Questions

  • SURFACE CHEMISTRY

    CHHAYA PUBLICATION|Exercise WARM UP EXERCISE|118 Videos

  • SURFACE CHEMISTRY

    CHHAYA PUBLICATION|Exercise Question-Answer Zone for Board Examination|29 Videos

  • SOME p-BLOCK ELEMENTS

    CHHAYA PUBLICATION|Exercise PRACTIVE SET 11|15 Videos

Similar Questions

Explore conceptually related problems

1 mL of 10% NaCl solution on addition to 100 cm^(3) standard gold sol in presence of 10^(-4) gelatin just prevents the coagulation of that sol. Find the gold number of gelatin.

When 1 mL of 10% NaCl solution is added to 10 mL gold sol in presence of x g lyophilic colloid, coagulation is inhibited . The gold number of the colloid is -

What happens when NaCl solution is added to a gold sol?

An excess of acidic KI solution is added to 25 mL of a H_(2)O_(2) solution when iodine is liberated. 20 mL of 0.1 (N) sodium thio-sulphate solution is required to titrate the liberated iodine. Calculate the percentage strength, volume strength and strength in normality of the H_(2)O_(2) solution.

6.2 gm of a sample containing Na_2CO_3, NaHCO_3 & non volatile impurity on gentle heating loses 5% of its weight due to the reaction 2NaHCO_3 rarr Na_2CO_3 + CO_2 + H_2O Residue is dissolved in water to form 100 ml solution & its 10 ml portion requires 7.5 ml of 0.2 M aqueous solution of BaCl_2 for complete precipitation of carbonates . What is the weight of Na_2CO_3 in gm in the origin sample ?

10ml 0.05 N H_2SO_4 solution is mixed with 10 ml 0.1 N NaOH solution. The pH of the final mixture is

If the quantity of electricity required to liberate 2.6267 g of gold from a solution of gold salt is used for the the electrolysis of CuSO_(4) solution in presence of copper anode, then 1.26 g of copper gets dissolved. Find the oxidation number of gold in the gold salt. [Cu=63, Au=197]