The coagulation of 200 mL of a positive colloid took place when 0.73 g HCl was added to it without changing the volume much. The flocculation value of HCl for the colloid is -

Options

A. 100
B. 36.5
C. 0.365
D. 150

Explanation

200 mL of the colloid requires 0.73 g of HCl=`(0.73)/(36.5)=0.02 `mol=20m mol of HCl
1000 mL(1L) of the colloid will require
`=(20)/(200) xx 1000 = 100" m mol of HCl" `
Thus , the flocculation value of HCl for the colloid is 100.