White phosphorus reacts with chlorine and the product hydrolyses In the presence of water, Calculate the mass of HCI obtained by the hydrolysis of the product formed by the reaction of 62 g of white phosphorus with chlorine in the presence of water.

Explanation

`P_(4) + 6Cl_(2) to 4PCl_(3)`
`([PCl_(3) + 3H_(2)O to H_(3)PO_(3) + 3HCl] xx 4)/(P_(4) + 6Cl_(2) + 12 H_(2)O to 4H_(3)PO_(3) + 12HCl)`
1 mol white P produces 12 mol of HCl. Here , 62g white P is taken which is equaivalent to `(62)/(124) = (1)/(2)` mol. Therefore 6 mol HCl will be formed . Mass of 6 mol HCl =` 6 xx 36.5 = 219.0` g