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Using crystal field theory, draw energy level diagram, write electronic configuration of central metal atom/ion, determine magnetic moment value in the following :
`[FeF_(6)]^(3-),[Fe(H_(2)O)_(6)]^(2+),[Fe(CN)_(6)]^(4-)`

Text Solution

Verified by Experts

`[FeF_(6)]^(3-):`

No. of unpaired electrons = 5,
`therefore mu = sqrt(5(5+2))=sqrt(35)BM=5.92BM`
`[Fe(H_(2)O)_(6)]^(2+)`,

No. of unpaired electrons = 4 :
`mu=sqrt(4(4+2))=4.9BM`
`[Fe(CN)_(6)]^(4-)`:

No. of unpaired electrons `=0, mu=0`
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