`CH_(3)CI` undergoes hydrolysis much easily as compared to `C_(6)H_(5)CI`. Explain with reasons.

Explanation

In cholorobenzene `C_(6)H_(5)CI`, and unshared pair of electrons on the CI-atom, is involved in resonance with the ring `pi`- electrons. As a result, the C-CI bond acquired some double bond charactrer. Thus, the C-CI bond becomes much stronger and epulsion of the CI-atom from the ring cannot be affected easily. so, it is not easy to hydrolyse chlorobenzene, as it is carried out under extreme conditions (high temperature and pressure).

`underset("Chlorobenzene")(C_(6)H_(5)CI+NaOH)overset("high temperature")underset ("high pressure")(rarr)underset("Phenol")(C_(6)H_(5)OH)+NaCl`
On the other hand, theC-Cl bond in `CH_(3)-Ci` is unable to acuireany double bond character because similar electrons delocalisation is not possible. Thus, it is easy to hydrolyse `CH_(3)-Cl` under normal conditions.
`underset("Methyl chloride")(CH_(3)-Cl)+NaOH overset(Delta)(rarr)underset("Methanol")(CH_(3)OH)+NaCl`.