Which one of each pair undergoes S(N)I r...

Which one of each pair undergoes `S_(N)I` reaction readily and why?
(i) `CH_(2)=CHCH_(2)CH_(2)Cl, CH_(3)CH =CHCH_(2)Cl` .

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The carocation obtained from C-Cl bond cleavage of the second compound is stablised by resonance. Because of this, it undergoes `S_(N)1` reaction readily. On the other hand, being a primary substrate the first compound does not undergo `S_(N)1` reaction.

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Which one of each pair of compounds will undergo S_(N)1 reaction readily and why? (i) CH_(2)CH-CH_(2)CH_(2)Cl . CH_(3)CH=CHCH_(2)Cl .

Which one of each pair will not undergo S_(N)2 reaction and why? (i) (CH_3)_(3)C CH_(2)Cl, CH_(3)CH_(2)Cl .

Which one of each pair of compounds will undergo S_(N)1 reaction readily and why? (ii) CH_(3)OCH_(2)Cl, CH_(3)OCH_(2)CH_(2)Cl .

Which one of the pairs undergoes hydrolysis by aqueous KOH readily and Why? (i) C_(6)H_(5)CH_(2)Cl .

Which one of the pairs undergoes hydrolysis by aqueous KOH readily and Why? (ii) (CH_3)_(3)C Cl and (CD_3)_(3)C Cl .

In which of the following two compounds S_(N)2 reaction is faster? Give reason. CH_(3)CH_(2)CH_(2)Cl and CH_(3)CH_(2)CH_(2)I .

Which of the following compounds are optically active and why? (1) CH_(3)CHBrCH_(2)CH_(3) (2) (CD_(3))_(2)CHCH_(2)CH_(3)

Which one of the following pairs are more reactive in S_(N)2 reaction? Why? (iii) CH_(2)=CHBr and CH_(2)=CH-CH_(2)Br .

Arrange the compounds in the order of increasing S_(N)1 reactivity: ClCH_(2)CH=CHCH_(2)CH_(3) (I), CH_(3)C Cl=CHCH_(2)CH_(3) (II) and CH_(3)CH = CHCH_(2)CH_(2)Cl (III)

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