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CH(3)Cl does not undergo S(N)1 reaction ...

`CH_(3)Cl` does not undergo `S_(N)1` reaction and `(CH_3)_(3)C Cl` does not undergo `S_(N)2` reaction - why?

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`CH_(3)^(o+)` formed from `CH_(3)Cl` has the least stability. Thus, `CH_(3)Cl` does not undergo `S_(N)1` reaction as breaking of C-Cl is not feasible. On the other hand, in case of `(CH_3)_(3)C Cl`, backside attack of nucleophile is not possible due to steric hindrance. Thus, `(CH_3)_(3)C Cl` does not undergo `S_(N)2`.
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