During conversion of `R-OH to R-Cl` conversion, `SOCl_(2)` is a more suitable reagent as compared to HCl, `PCl_(5)` or `PCl_(3)`-why?

The most suitable reagent for the conversion of RCH_2OH rarr RCHO is

All the P - Cl bonds in PCl_(5) are not equivalent - why ?

At 473K, equilibrium constant K_(c) for decomposition of PCl_(5) is 8.3x10^(-3) . If decomposition is depicted as, PCl_(5)(g)hArr PCl_(3)(g)+Cl_(2)(g), DeltaH_(r)^(0)=124.0kJ*mol^(-1) Write an expression for the reaction.

Write the Kp expression for PCl_(5(g))hArr PCl_(3(g)) + Cl_(2(g))

At 473K, equilibrium constant K_(c) for decomposition of PCl_(5) is 8.3x10^(-3) . If decomposition is depicted as, PCl_(5)(g)hArr PCl_(3)(g)+Cl_(2)(g), DeltaH_(r)^(0)=124.0kJ*mol^(-1) What would be the effect on K_(c) if (i) more PCl_(5) is added (ii) presure is increased (iii) the temperature is increased?

Describe the hybridisation in case of PCl_(5) . Why are the axiial bonds longer as compared to equatorial bonds?

At 473K, equilibrium constant K_(c) for decomposition of PCl_(5) is 8.3x10^(-3) . If decomposition is depicted as, PCl_(5)(g)hArr PCl_(3)(g)+Cl_(2)(g), DeltaH_(r)^(0)=124.0kJ*mol^(-1) What is the value of K_(c) for the reverse reaction at the same temperature?

Which of the following relations are true for the reaction, PCl_(5)(g)toPCl_(3)(g)+Cl_(2)(g) -

Describe the hybridisation in case of PCl_5 . Why are the axial bonds longer as compared to equatorial bonds?