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After standing in aqueous acid, (R)-2-bu...

After standing in aqueous acid, (R)-2-butanol is found to have lost its optical activity. Explain this observation.

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an achiral carbocation is formed which undergoes attack by `H_(2)O` form both sides equally well to form `(+-)`-2-octanol and so, the solution turns optically inactive.
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CHHAYA PUBLICATION-HALOAKANES AND HALOARENES-Exercise - Short answer type questions
  1. Which one of each pair will not undergo S(N)2 reaction and why? (i) ...

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  2. Which one of each pair will not undergo S(N)2 reaction and why? (ii)...

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  3. After standing in aqueous acid, (R)-2-butanol is found to have lost it...

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  4. Which one of each pair of compounds will undergo S(N)1 reaction readil...

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  5. Which one of each pair of compounds will undergo S(N)1 reaction readil...

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  6. In which reaction does recemisation occurs and why?

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  7. Prove that in S(N)2 reaction inversion of configuration takes place.

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  8. Arrange in increasing priority: -CH(2)CH(3), -CD(2)CH(3), -CH(3),-NH(2...

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  9. How can an asymmetric carbon be designated as R or S?

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  10. What is the necessary and sufficient condition for a molecule to show ...

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  11. What do you mean by enantiomers and diastereoisomers?

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  12. What do you mean by meso-compound and racemic modication? Explain why ...

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  13. What is Saytzef rule? Explain with an example.

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  14. Although haloalkanes can be prepared from alcohols, haloarenes cannot ...

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  15. The dipole moment of chlorobenzene is lower than that of cyclohexyl ch...

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  16. Why is chlorobenzene inert towards S(N)1 and S(N)2 reactions?

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  17. Explain why the melting point of p-dichlorobenzene is higher than that...

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  18. Arrange chlorobenzene, p-chloronitrobenzene and m-chloronitrobenzene i...

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  19. How is chloroform preserved and why?

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  20. What are Freons? How can Freon-12 be prepared? Mention its uses and ph...

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