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Two reactions R1 and R2 have identical p...

Two reactions `R_1 and R_2` have identical pre-exponential factors. Activation energy of `R_1` exceeds that of `R_2` by `10Kj.mol^(-1)`. If `K_1 and K_2` are rate constants for reactions `R_1 and R_2` respectively at 300K , then in `(K_2//K_1)` is equal to -(`R = 8.314J .mol^(-1).K^(-1)`)

A

12

B

6

C

4

D

8

Text Solution

Verified by Experts

The correct Answer is:
C
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