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In the electrochemical cell- Zn|ZnSO(4...

In the electrochemical cell-
`Zn|ZnSO_(4)(0.01M)||CuSO_(4)(1.0M)|Cu`, the emf of this Daniel cell is `E_(1)`. When the concentration of `ZnSO_(4)` is changed to 1.0M and that of `CuSO_(4)` changed to 0.01M, the emf changes to `E_(2)`. From the following , which one is the relationship between `E_(1)` and `E_(2)` ? (Given , `(RT)/(F) = 0.059`)

A

`E_(1) =E_(2)`

B

`E_(1) lt E_(2)`

C

`E_(1) gt E_(2)`

D

`E_(2) = equalnot E_(1)`

Text Solution

Verified by Experts

The correct Answer is:
C
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