Calculate the wavelength in nanometers of a quantum of light with frequency of `8times10^(15)s^(-1)` .The given value of Planck's constant is `6.63times10^(-34)Js` .The velocity of light is `3.0times10^(8)ms^(-1)`

Calculate the wavelength in nanometers of a quantum of light with frequency of 8×10^(15)s^(-1) .The given value of Planck's constant is 6.63×10^(-34)Js .The velocity of light is 3.0×10^(8)ms^(-1) . (A) 3.2×10^(7), (B) 2.5×10^(-25) (C) 5×10^(-18) (D) 40

The value of Planck's constant is 6.62618 xx 10^(-34)Js . The number of significant figures in it is

Calculate the wavelength , frequency and wave number of a light wave whose time period is 3 xx 10^(-10)s .

One milliwatt of light of wavelength 4560 A is incident on a cesium surface. Calculate the photoelectric current liberated assuming a quantum efficiency of 0.5 %. Given Planck's constant h=6.62xx10^(-34)J-s and velocity of light c=3xx10^(8)ms^(-1) .

The energy of a photon wavelength k = 1 meter is (Planck's constant = 6.625 xx 10^(-34) Js, speed of light = 3 xx 10^(8) m//s )