If `log_2 (log_2 (log_3 x)) = log_2 (log_3 (log_2 y))=0`, then the value of `(x+y)` is

log_2 [log_3(log_2 x)]=1

if log_2 x+ log_2 y >= 6 then the least value of x+y

If log_(2)(log_(2)(log_(3)x))=log_(3)(log_(3)(log_(2)y))=0 , then x-y is equal to :

If log_(2)(log_(2)(log_(3)x))=log_(3)(log_(3)(log_(2)y))=0 , then x-y is equal to :

If log_2 (log_3 (log_4 x))= 0, log_4 (log_3 (log_2 y))= 0 and log_3(log_4 (log_2z ))= 0, then the correct option is

If log_2(log_3(log_4(x)))=0, log_3(log_4(log_2(y)))=0 and log_4(log_2(log_3(z)))=0 then the sum of x,y,z is

if log_2(log_3(log_4x))=0 and log_3(log_4(log_2y))=0 and log_3(log_2(log_3z))=0 then find the sum of x, y and z is

If log_2 log_3 log_4 (x+1) =0, then x is :-

log_(2)(log_(2)(log_(3)x))=log_(2)(log_(2)(log_(2)y))=0 find (x+y)=?