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In Delta ABC, (sin((2pi)/3-A)+sin((2pi)/...

In `Delta ABC, (sin((2pi)/3-A)+sin((2pi)/3-B)+sin((2pi)/3-C))/(cos(pi/3-A/2)*cos(pi/3-B/2)*cos(pi/3-C/2)))` equals

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The value of the determinant |(sintheta, costheta, sin2theta) , (sin(theta+(2pi)/3), cos(theta+(2pi)/3), sin(2theta+(4pi)/3)) , (sin(theta-(2pi)/3), cos(theta-(2pi)/3), sin(2theta-(4pi)/3))|

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I. Sin^(-1)("sin"(2pi)/3)=(2pi)/3 II. Cos^(-1)("cos"(5pi)/4)=(5pi)/4