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Express log4a +log8a^(1/3)+ 1/loga8 as a...

Express `log_4a +log_8a^(1/3)+ 1/log_a8` as a logarithm to the base 2.

Text Solution

Verified by Experts

Here, we will use,
`log_(b^c)a = 1/clog_ba`
`log_ba = 1/log_ab`
`log_ba^c = clog_ba`
Now,
`log_4a+log_8a^(1/3) +1/(log_a8)`
`=log_(2^2)a +log_(2^3)a^(1/3)+1/log_a(2^3)`
...
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