If the equation `x^2+2x+5=0` has two roots `alpha and beta` then the equation whose roots are `alpha+1/alpha and beta+1/beta` is

The roots of the equation x^2+3x+4=0 are alpha and beta .Form the equations whose roots are (alpha+beta)^2 and (alpha-beta)^2

If alpha and beta are roots of x^(2)-2x+3=0, then the equation whose roots are (alpha-1)/(alpha+1) and (beta-1)/(beta+1) will be

If alpha, beta are the roots of x^(2)+2x+5=0 , then the equation whose roots are (alpha+1)/(alpha), (beta+1)/(beta) is

If alpha, beta are the roots of x^(2)+2x+5=0 , then the equation whose roots are (alpha+1)/(alpha), (beta+1)/(beta) is

if alpha,beta are the roots of the equation x^(22)x+5=0 obtain the equation whose roots are alpha^(3)+alpha^(2)-alpha+22 and beta^(3)+4 beta^(2)-7 beta+35?

If alpha,beta are the roots of x^(2)+2x+5=0 ,then the equation whose roots are (alpha+1)/(alpha),(beta+1)/(beta) is

If alpha,beta be the two roots of the equation x^2+x+1 =0, then the equation whose roots are alpha/beta and beta/alpha is

IF alpha and beta are the roots of 2x^2 + x + 3=0 , then the equation whose roots are ( 1- alpha ) /( 1 + alpha ) and ( 1- beta ) /( 1 + beta ) is

If alpha,beta are the roots of the equation x^(2)-2x+3=0 obtain the equation whose roots are alpha^(3)-3 alpha^(2)+5 alpha-2 and beta^(3)-beta^(2)+beta+5