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If x in ((3pi)/2,2pi), then 4cos^2(pi/2-...

If `x in ((3pi)/2,2pi),` then `4cos^2(pi/2-x)+4sqrt(cos2x+sin^4x)` equals

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If x in (pi,(3pi)/2), then 4cos^2(pi/4-x/2)+sqrt(4sin^4x+sin^2 2x) is always equal to (a) 1 (b) 2 (c) -2 (d) none of these

If x in (pi,(3pi)/2), then 4cos^2(pi/4-x/2)+sqrt(4sin^4x+sin^2 2x) is always equal to (a) 1 (b) 2 (c) -2 (d) none of these

If x in (pi,(3pi)/2), then 4cos^2(pi/4-x/2)+sqrt(4sin^4x+sin^2 2x) is always equal to (a) 1 (b) 2 (c) -2 (d) none of these

cos ((3pi)/( 4) + x) - cos((3pi)/( 4) -x) =- sqrt2 sin x

cos ((3pi)/( 4) + x) - cos((3pi)/( 4) -x) =- sqrt2 sin x

cos ((3pi)/( 4) + x) - cos((3pi)/( 4) -x) =- sqrt2 sin x

Prove that cos((3pi)/4+x)-cos((3pi)/4-x)= -sqrt2 sinx

cos((3pi)/(4)+x)-cos((3pi)/(4)-x) = -sqrt(2)sinx

cos((3pi)/(4)+x)-cos((3pi)/(4)-x) = -sqrt(2)sinx