A particle of mass 3 kg moves under a froce of `[4 hati + 8 hatj+ 10 hatk]` newton . Calcutale the acceleration (as vector) to which the particle is subjected. If the particle starts from rest and was at the origin initially. What are its new co - ordinates after 3 s?

Explanation

We Know that according to Newton's law of motion
`vecF = mveca" "i.e., " "veca = vecF//m`
But as here `vecF = 4 hati + 8 hatj + 10 hatk and m=3 kg`
`veca = (1//3) [4 hati + 8hatj + 10 hatk]m//s^(2)`
Futher according to the question of mation
`vecs = vecut +(1//2) vecat^(2)`
`vecs = 0 xx 3 + (1//2) (1//3) [ 4hati + 8 hatj + 10 hatk]xx 3^(2)`
`i.e.," "vecs = [6hati + 12 hatj+ 15hatk]`
so the co-ordinates of hte particle after 3 as are [6,12,15].