Under a force `( 10 hati - 3 hatj + 6 hatk)` newton a body of mass 5 kg moves from position `( 6 hati + 5 hatj - 3 hatk)` m to position `( 10 hati - 2hatj+ 7hatk)` m . Deduce the work done.

Explanation

To find the work done by the force on the body as it moves from one position to another, we can follow these steps:

### Step 1: Determine the initial and final position vectors
The initial position vector \( \mathbf{R_1} \) is given as:
\[ \mathbf{R_1} = 6 \hat{i} + 5 \hat{j} - 3 \hat{k} \]
The final position vector \( \mathbf{R_2} \) is given as:
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