If the vectors `(hati+ hatj + hatk)` and `3 hati` from two sides of a triangle, then area of triangle is :

Options

A. `sqrt(3)`
B. `2sqrt(3)`
C. `3//sqrt(2)`
D. `3sqrt(2)`

Answer

C

Explanation

`vecA xx vecB =|{:(hati,hatj,hatk),(1, 1, 1),(3,0,0):}|= 3(hati - hatk)`
Area of `Delta = (1)/(2)|vecA xx vecB| =(3)/(2)|hatj - hatk| =(3)/(2) sqrt(2) =(3)/(sqrt(2)`