To get a rsultant displacement of 10m, two displacement vectors, one of magnetic 6 m and another of 8 m,should be combined :

Options

A. parallel
B. anti-parallel
C. at an angle `60^(@)`
D. perpendicular to each

Answer

D

Explanation

Let `|vecr_(1)|= 6m " "|vecr_(2)|= 8m and |vecr|=10m`
Then `sqrt(r_()^(2) + r_(2)^(2) + 2r_(1)r_(2) cos theta) = 10`
`6^(2) + 8^(2) + 2r_(1)r_(2) cos theta = 10^(2)`
`" "cos theta = 0^(@)`
`" "theta= (pi)/(2)`