A force `F=ahati+bhatj+chatk` is acted upon a body of mass `m`. If the body starts from rest and was at athe origin initially, find its new coordinate after time `t`.

Options

A. `(at^(2))/(2m),(bt^(2))/(2m),(ct^(2))/(2m)`
B. `(at^(2))/(2m),(2bt^(2))/(m),(ct^(2))/(2m)`
C. `(at^(2))/(m),(bt^(2))/(m),(ct^(2))/(2m)`
D. none of these

Answer

A

Explanation

`x=(1)/(2)((a)/(m))t^(2) hati`
`y=(1)/(2) ((b)/(m) )t^(2) hatj`
`z=(1)/(2)((c)/(m))t^(2)(hatk)`