For a particle in uniform circular motion , the acceleration ` vec(a)` at a point ` p ( R, theta )` on the circle of radiu ` R` is ( Here ` theta` is measured from the ` x- axis` )

Options

A. `-(v^(2))/(R) sin theta hati + (v^(2))/(R) cos theta hatj`
B. `-(v^(2))/(R) cos theta hati + (v^(2))/(R) sin theta hatj`
C. `-(v^(2))/(R) cos theta hati + (v^(2))/(R) sin theta hatj`
D. `-(v^(2))/(R)hati + (v^(2))/(R) hatj`

Answer

B

Explanation

`veca = a_(x)hati - a_(y) hatj`
`veca= (v^(2))/(R) cos theta hati - (v^(2))/(R) sin theta hatj`