Linear momentum of an object can be expressed as `vecP= (4 cos t)hati+( 4 sin t)hatj`. Angle between the forces acting on the object and its linear momentum is :

Options

A. `(pi)//(2)`
B. `(pi)//(4)`
C. `(3pi)//(4)`
D. `pi`

Answer

A

Explanation

`" "vecP=(4 cos t)hati + (4 sin t)hatj`
`therefore" "vecF= (dvecP)/(dt)=(-4 sin t)hati +(4 cos t)hatj`
`thereforevecF. vecP= 0 rArr theta = pi//2`