Home
Class 11
PHYSICS
The velocity of a particle is v=6hati+2h...

The velocity of a particle is `v=6hati+2hatj-2hatk` The component of the velocity parallel to vector `a=hati+hatj+2hatk` invector from is

A

`6hati + 2hatj + 2hatk`

B

`2hati + 2hatj + 2hatk`

C

`hati + hatj + hatk`

D

`6hati + 2hatj - 2hatk`

Text Solution

Verified by Experts

The correct Answer is:
B
`(vecV, hata)=hata=[(6hati+2hatj -2hatk).(hati+ hatj+hatk)/(sqrt(33))]((hati+ hatj+hatk)/(sqrt(3)))`
`" "=(6 +2 -2)/(3)(hati +hatj+hatk)`
`" "2hati +2hatj+2hatk`
Promotional Banner

Topper's Solved these Questions

  • VECTORS

    GRB PUBLICATION|Exercise MORE THAN ONE CHOICE IS CORRECT|15 Videos

  • VECTORS

    GRB PUBLICATION|Exercise ASSERTION- REASON|1 Videos

  • VECTORS

    GRB PUBLICATION|Exercise PROBLEMS FOR PARCTICE|23 Videos

  • UNITS AND DIMENSIONS

    GRB PUBLICATION|Exercise Link Compression|6 Videos

Similar Questions

Explore conceptually related problems

The velocity of a particle is vecv=3hati+2hatj+3hatk .Find the vector component of the velocity along the line hati-hatj+hatk and its magnitude.

The velocity of a particle is 3hati+2hatj+3hatk . Find the vector component of the velocity along the line hati-hatj+hatk and its magnitude.

The component of hati in the direction of vector hati+hatj+2hatk is

The angular velocity of a particle is vec(w) = 4hati + hatj - 2hatk about the origin. If the position vector of the particle is 2hati + 3hatj - 3hatk , then its linear velocity is

The vector component of vector vecA =3hati +4hatj +5hatk along vector vecB =hati +hatj +hatk is :

A vector coplanar with vectores hati + hatj and hatj + hatk and parallel to the vector 2 hati - 2 hatj - 4 hatk is

Show that the vector A = (hati) - (hatj) + 2 hatk is parallel to a vector B = 3hati - 3hat + 6hatk .

The componant of vector 2 hati -3 hatj +2hatk perpendicular to the vector hati + -3 hatj + hatk is-

GRB PUBLICATION-VECTORS-OBJECTIVE QUESTIONS
  1. A vector vecA is rotated through angle theta about its tail. Chan...

    Text Solution

    |

  2. A particle is moving on a circular path with a constant speed 'v'. ...

    Text Solution

    |

  3. Linear momentum of an object can be expressed as vecP= (4 cos t)ha...

    Text Solution

    |

  4. vecA and vecB are two vectors. (vecA + vecB) xx (vecA - vecB) can...

    Text Solution

    |

  5. Vertices of a triangle are A(3, 1, 2), B(1, -1, 2) and C(2, 1, 1). ...

    Text Solution

    |

  6. A vector remins unchanged on :

    Text Solution

    |

  7. The velocity of a particle is v=6hati+2hatj-2hatk The component of the...

    Text Solution

    |

  8. A particle is displaced from a position 2hati-hatj+hatk (m) to another...

    Text Solution

    |

  9. Two vectors vecP and vecQ that are perpendicular to each other are ...

    Text Solution

    |

  10. The angle between the two vectors vecA=5hati+5hatj and vecB=5hati-5hat...

    Text Solution

    |

  11. A paricle starting from the origin (0,0) moves in a straight line in (...

    Text Solution

    |

  12. The sum of two vectors A and B is at right angles to their difference....

    Text Solution

    |

  13. If vecA=2hati+3hatj-hatk and vecB=-hati+3hatj+4hatk then projection of...

    Text Solution

    |

  14. A particle acted upon by constant forces 4hati +hatj- 4 hatk and ...

    Text Solution

    |

  15. The component of vector A=a(x)hati+a(y)hatj+a(z)hatk and the directioi...

    Text Solution

    |

  16. The angle subtended by vector vecA = 4 hati + 3hatj + 12hatk with t...

    Text Solution

    |

  17. vecA and vecB are two vectors gives by vecA = 2 hati + 3hatj and ve...

    Text Solution

    |

  18. Given vecC = vecA xx vecB and vecD = vecB xx vecA. What is the angle ...

    Text Solution

    |

  19. The resultant of two vectors vecP andvecQ is vecR. If the magnitude...

    Text Solution

    |

  20. A particle moves in the xy plane under the influence of a force such t...

    Text Solution

    |