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vecA and vecB are two vectors gives by...

`vecA` and `vecB` are two vectors gives by `vecA = 2 hati + 3hatj and vecB = hati +hatj`. The magnetiude of the component of `vecA` along `vecB` is :

A

`(5)/(sqrt(5))`

B

`(3)/(sqrt(2))`

C

`(7)/(sqrt(2))`

D

`(1)/(sqrt(2))`

Text Solution

Verified by Experts

The correct Answer is:
A
`vecA .vecB = (2hati + 3hatj).((hati + hatj)/(sqrt(2)))`
`=(2+3)/(sqrt(2))=(5)/(sqrt(2))`
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