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If a particle of mass m is moving with c...

If a particle of mass `m` is moving with constant velocity `v` parallel to `x`-axis in `x-y` plane as shown in fig. Its angular moment with respect to origin at any time `t` will be

Text Solution

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We know that
Angular momentum `vecL = vecr xx vecp` in terms of components becomes
`|{:(hati,hatj, hatk),(x,y,z),(p_(x),p_(y), p_(z)):}|`
AS motion is in x-y plane (i.e., z = 0 and `p_(x) = 0`)
`vecL = hatK(xp_(y) - yp_(x))" "......(i)`
Here x= vt, y= b, `p_(x)= mv` and `p_(y)=0`
So, `vecL = hatK[vt xx 0 bmv] = - mub hatk`" "(ii)`
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