The bulk modulus of water is 2.0xx10^(9)...

The bulk modulus of water is `2.0xx10^(9) N//m^(2)`. The pressure required to increase the density of water by `0.1%` is

`2xx10^(9)" newton /metre"^(2)`

`2xx10^(8)" newton /metre"^(2)`

`2xx10^(6)" newton /metre"^(2)`

`2xx10^(4)" newton /metre"^(2)`

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The correct Answer is:

`B=(-Vdp)/(dV)`
`:. dp=(-BdV)/(V)`
`:. dp=B (dp)/(rho)`
`" " =2xx10^(9)xx10^(-3)`
`" " =2xx10^(6)Pa`

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