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The loop ABCD is moving with velocity 'v...

The loop `ABCD` is moving with velocity `'v'` towards right. The magnetic field is `4T`. The loop is connected to a resistance of `8 Omega`. If steady current of `2A` flows in the loop then value of `'v'` if loop has a resistance of `4 Omega`, is : (Given `AB = 30 cm, AD = 30 cm`)

A

`(50)/(3) m//s`

B

20 m/s

C

10 m/s

D

`(100)/(3) m//s`

Text Solution

Verified by Experts

The correct Answer is:
D
`e=BVlsin37^(@)=BVl(3)/(5)`
`e=(36V)/(50)`
`i=(e)/(8+4)=2`
e=24
`(360V)/(50) =24`
`V=(50xx24)/(36)rArr(50xx2)/(3)rArr(100)/(3)`
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