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A 50 Hz AC source of 20 V is connected a...

A `50 Hz AC` source of `20 V` is connected across `R ` and `C` as shown in figureure.

The voltage across `R` is `12 V`. The voltage across `C` is

A

8 V

B

16 V

C

10 V

D

not possible to determine unless values of R and C are given

Text Solution

Verified by Experts

The correct Answer is:
B
`V_("source")=sqrt(V_(R)^(2)-V_(C)^(2))`
`:. V_(C)=sqrt(V_("Source")^(2)+V_(C)^(2))`
`" " sqrt((20)^(2)-(12)^(2))=16V`
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