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Dual of (x'^^y')=xvvy is...

Dual of `(x'^^y')=xvvy` is

A

`(x'^^y')=x^^y`

B

`(x' vvy')=x^^y`

C

`(x' vvy')=xy`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B
Obviously, In dual `'^^'` is changed to `'vv'` and `'vv'` is changed to `'vv'`
So, dual of `(x'^^y')'=xvvy`
is `(x' vv y')=x^^ y`
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