A river is flowing due east with a speed `3m//s`. A wimmer can swim in still water at a speed of `4 m//s`. If swimmer starts swimming due north, what will be his resultant velocity (magnitude and direction) ?

Options

A. `5 m//s` at `37^(@)` to `N`
B. `5 m//s` at `53^(@)` to `N`
C. `10 m//s` at `37^(@)` to `N`
D. None of these

Answer

A

Explanation

`V_("net") = sqrt((3^(2) + 4^(2))) = 5 m//s` at `tan^(-1) ((3)/(4))`
`= 5m//s` at `37^(@)` to N.