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If 30g of a solute of molecular weight 1...

If `30g` of a solute of molecular weight `154` is dissolved in `250 g` of benzene. What will be the elevation in boiling point -
(Given : `K_(b(C_(e)H_(6))) = 2.6 K Kg mol^(-1))`

A

`3.05`

B

`2.05`

C

`4.05`

D

`10`

Text Solution

Verified by Experts

The correct Answer is:
B
`DeltaT_(b)=(K_(b) xx w xx 1000)/(W xx "mol.wt")`
`DeltaT_(b) = (2.6 xx 30 xx 1000)/(250 xx 154)`
`DeltaT_(b) = (78 xx 4)/(154) = 2.05`
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