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Slope of line zbar(a)+barzoverset(.)(a)+...

Slope of line `zbar(a)+barzoverset(.)(a)+b=0, b in R ` is -

A

`(-Re(a))/(Im(a))`

B

`(-Im(a))/(Re(a))`

C

`(Re(a))/(Im(a))`

D

None of these

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To find the slope of the line given by the equation \( \overline{z}(a) + \overline{z}(a) + b = 0 \), where \( b \in \mathbb{R} \), we can follow these steps: ### Step 1: Express \( z \) in terms of real and imaginary parts Let \( z = x + i y \), where \( x \) is the real part and \( y \) is the imaginary part of the complex number \( z \). ### Step 2: Substitute \( z \) into the equation Substituting \( z \) into the equation gives us: \[ \overline{z} = x - i y \] Thus, the equation becomes: \[ (x - i y)(a) + (x + i y)(a) + b = 0 \] ### Step 3: Simplify the equation Expanding the equation, we have: \[ (xa - i ya) + (xa + i ya) + b = 0 \] This simplifies to: \[ 2xa + b = 0 \] The imaginary parts cancel out. ### Step 4: Rearranging to find the slope Now, we can rearrange the equation to isolate \( y \): \[ 2xa = -b \] This implies: \[ y = -\frac{b}{2a} \] ### Step 5: Identify the slope In the context of a line in the Cartesian plane, the slope \( m \) can be identified from the equation \( y = mx + c \). Here, the slope \( m \) is given by: \[ m = -\frac{b}{2a} \] ### Conclusion Thus, the slope of the line is: \[ -\frac{b}{2a} \] ---

To find the slope of the line given by the equation \( \overline{z}(a) + \overline{z}(a) + b = 0 \), where \( b \in \mathbb{R} \), we can follow these steps: ### Step 1: Express \( z \) in terms of real and imaginary parts Let \( z = x + i y \), where \( x \) is the real part and \( y \) is the imaginary part of the complex number \( z \). ### Step 2: Substitute \( z \) into the equation Substituting \( z \) into the equation gives us: \[ ...
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