Two particles of equal mass (m) each move in a circle of radius (r) under the action of their mutual gravitational attraction find the speed of each particle.

Options

A. `(GM)/(R)`
B. `sqrt([2sqrt2(GM)/(R)])`
C. `sqrt([(GM)/(R)(2sqrt2+1)])`
D. `sqrt([(GM)/(R)(((2sqrt2+1))/(4))]`

Answer

D

Explanation

`(mv^(2))/(R)=F_("net")`
`v=sqrt((GM)/(R)[(2sqrt2+1)/(4)]`