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The length of simple pendulum executing ...

The length of simple pendulum executing SHM is increased by `69%` The percentage increase in the time period of the pendulum is

A

`30%`

B

`11%`

C

`21%`

D

`42%`

Text Solution

Verified by Experts

The correct Answer is:
A

`(T)/(T)=sqrt((169)/(100)), T=(13)/(10)T`
`((T)/(T)-1)xx100%=((13)/(10)-1)xx100%=30%`
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Knowledge Check

  • Time period of simple pendulum is

    A
    `T = 2pi sqrt(l/g)`
    B
    `T = 2pi sqrt(g/l)`
    C
    `T = sqrt(2 pi (l)/(g))`
    D
    `T = (1)/(2pi) sqrt(g/l)`
  • The length of a simple pendulum is increased by 44%. The percentage increase in its time period will be

    A
    0.44
    B
    0.22
    C
    0.2
    D
    0.11
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    A
    `10%`
    B
    `20%`
    C
    `40%`
    D
    `44%`
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