If the volume of a block os aluminium is decreased be `1%` the pressure (stress) on is surface is increased by (Bulk moduals) of `Al=7.5xx10^(10)Nm^(-2))`

Options

A. `7.5xx10^(10)Nm^(-2)`
B. `7.5xx10^(8)Nm^(-2)`
C. `7.5xx10^(6)Nm^(-2)`
D. `7.5xx10^(4)Nm^(-2)`

Answer

B

Explanation

Given, `(DeltaV)/(V)=1%=(1)/(100)`
Bulk modulus, `B=(P)/(DeltaV//V)=(PV)/(DeltaV)`
or `P=(BDeltaV)/(V)=7.5xx10^(10)xx(1)/(100)`
`=7.5xx10^(8)Nm^(-2)`