How many mazimum posssible set (s) of quantum no . Are possible for `6^(th)` electron of Fe ?

Options

A. 1
B. 3
C. 6
D. 10

Answer

c

Explanation

Sixth electrons of Fe means

so for 2p `e^(-) n=2,l=1,m=+,0-1 `
so no of set `implies n=2,l=1,m=+1,s=+-(1)/(2)`
`n=2,l=1,m=-1,s=+-(1)/(2)`
`n=2,l-1,m=-1,s=+-(1)/(2)`
total 6 sets are possible .