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Magnetic moment of Fe^(a+)(Z= 26 ) is sq...

Magnetic moment of `Fe^(a+)(Z= 26 )` is `sqrt 24 BM`. Hence number of unpaired electron and value of 'a' respectively are :

A

4,2

B

2,4

C

3,1

D

0,2

Text Solution

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The correct Answer is:
a
`X^(n+) to d^(6)` configuartion
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