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{:(, "column"-I,, "column-II"),((a) ,"31...

`{:(, "column"-I,, "column-II"),((a) ,"31.4 % more neutrons as compared to protons ", (p) ,""_(7)^(14)N),((b),"11.1 % more neutrons than electrons" ,(q),""_(26)^(56)Fe^(3+)),((c ) , "30.4 % more neutrons than electrons ",(r),""_(17)^(37)Cl^(-)),((d),"Same number of neutrons and protons ",(s),""_(35)^(81)Br):}`

Text Solution

Verified by Experts

The correct Answer is:
(a-s);(b-r);((c-s);(d-r)
(a) `(81-2xx35)/(35)xx100=31.4%(._(35)^(81)Br)`
(b) `(20-18)/(18)xx100=11.1%(._(17)^(37)Cl^(-))`
(c) `(30-23)/(23)xx100=30.4%(._(26)6(56)Fe^(3+))`
(d) `._(7)^(14)NrArr`No. of 'p' `=7=`no. of 'n'
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Species X with mass number 37 contains 11.1 % more neutrons as compared to electrons , then what is the incorrect repesentation of element x?