If an orbital can have maximum 4 electrons then, how many elements can be present in 8th period?

Options

A. 100
B. 75
C. 128
D. 64

Explanation

To determine how many elements can be present in the 8th period of the periodic table, given that an orbital can hold a maximum of 4 electrons, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Periodic Table Structure**:
The periodic table is organized into periods and blocks. Each period corresponds to the filling of different types of orbitals (s, p, d, f, etc.).

2. **Identifying the Blocks in the 8th Period**:
In the 8th period, we will have the following blocks:
- S block: 1 orbital
- P block: 3 orbitals
- D block: 5 orbitals
- F block: 7 orbitals
- G block: 9 orbitals (hypothetical for the 8th period)

3. **Calculating the Total Number of Orbitals**:
Adding the orbitals from each block gives us:
- S block: 1
- P block: 3
- D block: 5
- F block: 7
- G block: 9

Total orbitals = 1 + 3 + 5 + 7 + 9 = 25 orbitals.

4. **Calculating the Maximum Number of Electrons**:
Since each orbital can hold a maximum of 4 electrons, we multiply the number of orbitals by the number of electrons per orbital:
\[ \text{Maximum electrons} = \text{Number of orbitals} \times \text{Electrons per orbital} \]
\[ \text{Maximum electrons} = 25 \text{ orbitals} \times 4 \text{ electrons/orbital} = 100 \text{ electrons}. \]

5. **Conclusion**:
Since each element corresponds to one electron in the context of filling the orbitals, the maximum number of elements that can be present in the 8th period is 100.

### Final Answer:
The maximum number of elements that can be present in the 8th period is **100**.