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Which option is correct?...

Which option is correct?

A

3rd `I.E.` of `C gt N`

B

2nd I.E. of `N lt O`

C

1st I.E. of `F gtO`

D

All of these

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AI Generated Solution

The correct Answer is:
To determine which option is correct regarding ionization energies, we will analyze each statement provided in the question step by step. ### Step 1: Analyze the first statement **Statement:** Carbon's third ionization energy is more than nitrogen's. - **Electronic Configuration:** - Carbon: \(1s^2 2s^2 2p^2\) - Nitrogen: \(1s^2 2s^2 2p^3\) - **Ionization Process:** - For Carbon, removing three electrons (first two from 2s and one from 2p) leads to a configuration of \(1s^2\). - For Nitrogen, removing three electrons (first two from 2s and one from 2p) leads to a configuration of \(1s^2 2s^2\) (which is stable). - **Conclusion:** Removing the third electron from Carbon requires more energy due to the stable configuration of Nitrogen after removing three electrons. Therefore, this statement is **correct**. ### Step 2: Analyze the second statement **Statement:** The second ionization energy of nitrogen is less than that of oxygen. - **Electronic Configuration:** - Nitrogen: \(1s^2 2s^2 2p^3\) - Oxygen: \(1s^2 2s^2 2p^4\) - **Ionization Process:** - For Nitrogen, after removing one electron, the configuration becomes \(1s^2 2s^2 2p^2\). - For Oxygen, after removing one electron, the configuration becomes \(1s^2 2s^2 2p^3\). - **Stability Consideration:** The half-filled configuration of \(2p^3\) in Nitrogen is more stable than the \(2p^4\) configuration in Oxygen. Thus, removing a second electron from Oxygen is more difficult than from Nitrogen. - **Conclusion:** This statement is **correct**. ### Step 3: Analyze the third statement **Statement:** The first ionization energy of fluorine is greater than that of oxygen. - **Electronic Configuration:** - Fluorine: \(1s^2 2s^2 2p^5\) - Oxygen: \(1s^2 2s^2 2p^4\) - **Ionization Process:** - For Fluorine, removing one electron leads to \(1s^2 2s^2 2p^4\). - For Oxygen, removing one electron leads to \(1s^2 2s^2 2p^3\). - **Trend in Ionization Energy:** As we move from left to right across a period, ionization energy increases due to increasing nuclear charge and decreasing atomic size. - **Conclusion:** The first ionization energy of Fluorine is indeed greater than that of Oxygen. Thus, this statement is **correct**. ### Final Conclusion Since all three statements are correct, the correct option is: **Option 4: All of these are correct.** ---
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GRB PUBLICATION-PERIODIC TABLE-C.Ionisation Energy
  1. Which element having the following electronic configuration has minimu...

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  2. Select correct statement.

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  3. Which option is correct?

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  4. Which one of the following electronic configuration of an atom has the...

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  5. Identify the incorrect order of first ionization energy.

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  6. Amongst the following elements whose electronic configuration are give...

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  7. Which of the following ion of an element E (E belongs to 2nd period) h...

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  8. Higher values of ionisation energies of the 5d-transition elements are...

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  9. Metallic nature increases moving down the group because:

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  10. Select the correct statement.

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  11. Which of the following sequence regarding the first ionisation potenti...

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  12. The ionisation energy for 'Sc', 'Y' and 'La' are x,y and z kcal/mol re...

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  13. Select proper graph of 13th group ionization energy us. Its elements.

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  14. Second ionisation potential of Li,Be,B is in the order:

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  15. Select correct graph, which is plotted between ionisation energy of 2n...

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  16. For metal M, first ionisation energy is equal to 38 kcal/mole. Which o...

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  17. The ionisation enthalpy of lithium is much lower than that of helium d...

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  18. The first ionisation enthalpy (Delta(i)H^(o-)) values of the third per...

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  19. Correct order of IE(1) are: (P) Li lt B lt Be lt C (Q) O lt N lt F ...

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  20. If {:(X(g)^(-) rarr X(g)^(2) +3e^(-),DeltaH(1)= 900 kJ),(X(g) rarr X(g...

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